Freefall Artinya

Extreme-sports enthusiasts have been known to jump off the top of El Capitan, a sheer granite cliff of height 910 min Yosemite National Park. Assume a jumper runs horizontally off the top of El Capitan with speed 4.0 m/sand enjoys a free fall until she is h = 150 m above the valley floor, at which time she opens her parachute.(Figure 1) A) Ignoring air resistance how long is the jumper in freefall? Please show units B) How far from the cliff is the jumper when she opens her chute? Please show units

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• 1. Extreme-sports enthusiasts have been known to jump off the top of El Capitan, a sheer granite cliff of height 910 min Yosemite National Park. Assume a jumper runs horizontally off the top of El Capitan with speed 4.0 m/sand enjoys a free fall until she is h = 150 m above the valley floor, at which time she opens her parachute.(Figure 1) A) Ignoring air resistance how long is the jumper in freefall? Please show units B) How far from the cliff is the jumper when she opens her chute? Please show units

1. Extreme-sports enthusiasts have been known to jump off the top of El Capitan, a sheer granite cliff of height 910 min Yosemite National Park. Assume a jumper runs horizontally off the top of El Capitan with speed 4.0 m/sand enjoys a free fall until she is h = 150 m above the valley floor, at which time she opens her parachute.(Figure 1) A) Ignoring air resistance how long is the jumper in freefall? Please show units B) How far from the cliff is the jumper when she opens her chute? Please show units

The jumper in freefall for 152 s and the distance between the jumper and the cliff when she opens her parachute is 608 m according to the calculation as follows.

- Length of the freefall

sy = 1/2 gt²

sy / (1/2 g) = t²

2 sy / g = t²

√(2 sy / g) = t, or

t = √(2 sy / g), assume g = 10 m/s², hence

t = √(2. (910 m – 150 m) / (10 m/s²))

t = √(2. 760 m / (10 m/s²))

t = √(1.520 m / (10 m/s²))

t = 152 s

- Distance between the jumper and the cliff

sx = vx. t

sx = 4 m/s. 152 s

sx = 608 m

Explanation

In Uniformly Accelerated Motion, at least you need to remember the following formula.

(1) v = v₀ + at

(2) v² = v₀² + 2 as

(3) s = v₀t + 1/2 at²

with:

v₀ = initial speed (m / s)

v = final speed (m / s)

a = acceleration (m / s²)

t = time (t)

s = mileage (m)

Acceleration can be positive or negative. If an object moves with a positive acceleration, it means that the object is moving faster. Meanwhile, if an object moves with a negative acceleration, it means that the object is moving more slowly.

In the question discussed, the jumper enjoys a free fall until she is 150 m above the valley floor (v₀y = 0 m / s). She falls down in the direction of gravity acceleration so that the speed increases. Thus, the Uniformly Accelerated Motion formulas that meet this phenomenon are as follows.

(1) vy = gt

(2) vy² = 2 gsy

(3) sy = 1/2 gt²

While the horizontal distance traveled by the jumpers from the starting point to touch the ground, you can use the Uniform Motion formula (because in the horizontal direction there is no acceleration that works so the initial speed and end speed are always the same), as follows.

sx = vx. t

Learn more

1. Material about Uniformly Accelerated Motion https://brainly.co.id/tugas/17018975

2. Material about a combination of Uniformly Accelerated Motion and Uniform Motion https://brainly.co.id/tugas/17071191

3. Material about parabolic motion https://brainly.co.id/tugas/17679138

------------------------------------------------------------------------- Answer Details

Grade: 8

Subject: Physics

Chapter: Chapter 1 - Motion

Code: 8.6.1

Keywords: Uniformly Accelerated Motion, accelerated, acceleration, Uniform Motion

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